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The concept of stochastic independence of random variables and how to determine if two random variables are stochastically independent. It also covers the concept of functions of random variables, including how to find the probability density function (pdf) of a function of a random variable. Examples are provided to illustrate these concepts.
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3
4
in the command area (Y) may be taken as independent,
if the command area is far removed from the reservoir.
Inflow
Reservoir
Command area
Rainfall
Independent Random Variables
6
Independent Random Variables
hence the conditional pdf is equalt to the marginal pdf.
( )
h(y) > 0
77
Independent Random Variables
independent if and only if their joint density is equal to
the product of their marginal densities.
p(x
i
, y
j
) = p(x
i
). p(y
j
) v i,j
Example-1(contd.)
( )
1 1
0 0
1
2
0
∫ ∫
( )
1 1
0 0
1
2
0
∫ ∫
9
Example-1(contd.)
f ( , x y ) ≠ g x h y ( ). ( )
10
Example-2(contd.)
( )
0 0
0
x y
x y x
∞ ∞
− +
∞
− − −
∫ ∫
∫
( )
0 0
0
x y
y x y
∞ ∞
− +
∞
− − −
∫ ∫
∫
12
Example-2 (contd.)
( )
x y
x y
− −
− +
f ( , x y ) = g x h y ( ). ( )
13
Functions of Random Variable
Example for discrete case
p(x) = 60/77x ; x = 2, 3, 4, 5
discrete values
y = x
2
-7x+
Distribution of y:
p(Y=-7) = p(X=3)+p(X=4) = 20/77+ 15/77 = 35/77 = 5/
p(Y=-5) = p(X=2)+p(X=5) = 30/77+ 12/77 = 42/77 = 6/
x 2 3 4 5
y -‐5 -‐7 -‐7 -‐
p(x) 30/77 20/77 15/77 12/
16
∞
−∞
18
1
4
y
P X
−
⎡ ⎤
≤
⎢ ⎥
⎣ ⎦
Example-
19
b. g(y) =
c. From 0 < x < 1, we get
( ) ( )
2
1
64
dG y y
d
dy dy
⎛ ⎞
−
⎜ ⎟
⎝ ⎠
( )
1
( ) 1 9
32
y
g y y
−
= < <
Example-1(contd.)
( )
21
y=4x+
9
1
9
9
2
1
1
2
( 1) 1 ( 1)
32 32 2
1
(8 0)
64
1
y y
dy
⎡ ⎤
− −
=
⎢ ⎥
⎣ ⎦
= −
=
22