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if the collision lasts for 0.0625 seconds calculate the force that acted on each mass duri, Quizzes of Physics

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2019/2020

Available from 05/08/2022

roneil-algara
roneil-algara 🇵🇭

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QUESTION
Answer
F1 = = 200 N , for 2.5kg
F2 = 382.592 N, for 4.9kg
Explanation
m1 = 2.5kg
m2 = 4.9kg
vf1 = 5m/s
vf2 = 4.88m/s
t = 0.0625s
For 2.5kg;
F1= m1a
= m1(vf1/t)
= 2.5(5/0.0625)
= 200 N
For 4.9kg;
F2 = m2(v2f/t)
= 4.9(4.88/0.0625)
= 382.592 N

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QUESTION

Answer F 1 = = 200 N , for 2.5kg F 2 = 382.592 N, for 4.9kg Explanation m 1 = 2.5kg m 2 = 4.9kg vf1 = 5m/s vf2 = 4.88m/s t = 0.0625s For 2.5kg; F 1 = m 1 a = m 1 (vf1/t) = 2.5(5/0.0625) = 200 N For 4.9kg; F 2 = m 2 (v2f/t) = 4.9(4.88/0.0625) = 382.592 N